# MKS unit

## MKS unit

An obsolete, non-SI (International System) unit of the metre-kilogram-second system.
References in periodicals archive ?
Do it with kilograms and meters per second, and E comes out as the MKS unit of energy: the joule.
y = [sq.root (hbar/m omega)] times coordinate variable X, (X meters) (m= 1 kg) (mks units) (angular velocity omega in radians per second) [20Hz = > omega = 20x2pi] [Ref.
Changing this result from Gaussian to MKS units yields the free-space permittivities
where [[mu].sub.0]/4[pi] = [r.sub.*][m.sub.*]/[e.sup.2.sub.*] = [r.sub.c]m/[e.sup.2.sub.*] = [10.sup.-7] in MKS units. Converting (A3) back into Gaussian units gives
These two parameters are normalized to MKS units in the MMICAD model.
where [[mu].sub.0]/4[pi] = [r.sub.*][m.sub.*]/[e.sup.2.sub.*] = [r.sub.c]m/[e.sup.2] = [10.sup.-7] in MKS units. Converting (A3) back into Gaussian units gives
Changing the units of the first equation in (7) from Gaussian to mks units [7] and solving for [[epsilon].sub.0] leads to
where [[epsilon].sub.0] is the electric permittivity of free space in mks units. Then, utilizing [[epsilon].sub.0][[mu].sub.0] = 1/[c.sup.2] leads to
The magnitude of [[mu].sub.0] is easy to remember--it is 4[pi]x[10.sup.-7] in mks units. Thus [r.sub.*][m.sub.*]/[e.sup.2.sub.*] in (9) had better equal [10.sup.-7] in mks units, and it does ([e.sub.*] in Gaussian units is obtained from (3) and G, or from (7) and h; and then changed into mks units for the calculation).
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