See my function looks like this, I added '1' inside the
absolute value as [absolute value of x + 1], then my graph appeared on the left side.
[absolute value of U[E.sub.jtq]] =
absolute value of firm j's unexpected earnings, measured as reported earnings for quarter q less earnings for quarter q - 4, scaled by market value of equity at the end of quarter q - 1.
The results presented here suggest that the observed correlations between the
absolute value of a price change and volume are not due to lagged effects of one variable upon another.
Since [[mu].sub.c], [[mu].sub.s] are undistinguishable by the sizes of their
absolute values, the idea of Stewart[ 17] was to store a new constant, namely,
In the sequel, given a matrix A, then [absolute value of A] denotes the matrix whose entries are the
absolute values of the entries of A.
The problem (3) is called the
absolute value variational inequality, which is a special form of the mildly nonlinear variational inequalities [11].
Thus, we define the not archimedean
absolute value over K(([X.sup.-1])) by [absolute value of [alpha]] = [[absolute value of X].sup.deg([alpha])] where [absolute value of X] > 1, and [absolute value of 0] = 0.
Suppose that R is a field which is complete with respect to an
absolute value [absolute value].
Thus, a natural question arises: Are there infinitely many positive integers n such that [absolute value of S(n+1) - S(n)] = 1, where [absolute value of x] denotes the
absolute value of x?
H := {z [member of] D :
absolute value of (z - 0.5)] > 0.5} onto D\K
In the analysis, the values can be applied either in [[OHM]] and [F], or in [[OHM] x m] and [F/m], since using the specific values in expression (2) instead of
absolute values, l and S are shortened, and the result remains the former.